A substance undergoes first order decomposition involving two parallel first order reaction as shown. The mole percent of $B$ in the products is:

23.17

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76.68

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30.16

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69.84

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Solution

The correct option is A $23.17$
For parallel reactions ratio of products is:
${(\frac{B}{C})}^{- 1} = (\frac{k_{1}}{k_{2}}) = 3.289$
$\frac{C}{B} = 3.289$
assuming some x for which $C : B = 3.289$ we find only solution is $23.17 %$ B

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