Question

A sugar syrup of weight $214.2$ g contains $34.2$ g of sugar $\left(C_{12}{H}_{22}{O}_{11}\right)$. Calculate. the molal concentration (Write your answer as 18X, where, X= molality)

Answer 1

Weight of solvent $=214.2-34.2=180g$

The molal concentration of the sugar syrup $m=\frac{W_2\times 1000}{M{w}_2\times W_1}=\frac{34.2\times 1000}{342\times 180}=5/9m$

Thus, the molal concentration of the sugar syrup in 10X $=10\times 5/9=10$ m.