Question

A suitcase with measures 80 cm $\times$ 48 cm $\times$ 24 cm is to be covered with a tarpaulin cloth. How many meters of tarpaulin of width 96 cm is required to cover 100 such suitcases?

Answer 1

Given: Length of suitcase box l = 80 cm,
Breadth of suitcase box b = 48 cm
And Height of cuboidal box h = 24 cm
Total surface area of suitcase box = 2(lb + bh + hl)
$=2(80\times 48+48\times 24+24\times 80)=2(3,840+1,152+1,920)=2\times 6,912=13,824c{m}^2$
Area of Tarpaulin cloth = Total surface area of suitcase
$\Rightarrow l\times b=13,824$
$\Rightarrow l\times 96=13,824$
$\Rightarrow l=\frac{13,824}{96}cm$
$\Rightarrow l=144cm$
Required tarpaulin for 100 suitcases = 144 $\times$ 100 = 14,400 cm = 144 m
Hence tarpaulin cloth required to cover 100 suitcases is 144 m.