Formula: 1 Mark
Steps: 2 Marks
Answer: 1 Mark
Given,
Principal = ₹ 56,000
Time = 2 years
Interest = ₹ 280
Let the rate of interest be R % p.a.
S.I=P×R×T100
⇒R=I×100P×T
⇒R=280×10056000×2
⇒R=280560×2
⇒R=14=0.25
∴ The rate of interest is 0.25 % .
We have to find the interest if the rate of interest was 11 %,
Interest = P×R×T100
On substituting the values we get,
Interest = 56000×11×2100 = ₹ 12320
Hence, the interest in two years if the rate was 11% is ₹ 12320.