CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A sum of money invested at compound interest amounts to Rs $$4624$$ in $$2$$ years and to Rs $$4913$$ in $$3$$ years. The sum of money is________


A
Rs 4360
loader
B
Rs 4260
loader
C
Rs 4335
loader
D
Rs 4096
loader

Solution

The correct option is D Rs $$4096$$
Let $$x$$ be the sum of money be $$x$$
S.I. on Rs. $$4624$$ for $$1$$ year $$=$$ Rs. $$(4913-4624)=$$ Rs. $$289$$.
$$\therefore $$ Rate $$=\dfrac {100\times 289}{4624\times 1}\%=6\dfrac {1}{4}\%$$
Now, $$x\left (1+\dfrac {25}{4 \times 100}\right)^2=4624$$ or $$x\times \dfrac {17}{16}\times \dfrac {17}{16}=4624$$
$$\therefore x=\left (4624\times \dfrac {16}{17}\times \dfrac {16}{17}\right)$$
$$\therefore x=$$ Rs. $$4096$$
Thus, the sum of money is Rs. $$4096$$.

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image