A sum of money is rounded off to the nearest rupee. The probability that the round off error is at most 10 paise is
A
1/10
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B
11/100
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C
3/25
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D
None of these
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Solution
The correct option is D None of these Sample Space is {−0.50,−0.49,...,0,0.01,...,0.49}. n(S)=100 and the sound off error is at most 10 paise if A={−0.10,−0.09,...,0.10} n(A)=20 Therefore, Required probability is 20100.