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A sum of $R s 500$ is in the form of notes of denominations of $R s 5$ and $R s 10$ . If the total number of notes is $90$ , find the number of notes of each type.

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Solution

$L e t t h e n u m b e r o f R s 5 n o t e s b e x$

$H e n c e t h e n u m b e r o f R s 10 n o t e s b e (90 - x)$

$T o t a l s u m o f m o n e y = R s 500$

$∴ 5 x + 10 (90 - x) = 500$

$5 x + 900 - 10 x = 500$

$- 5 x = 500 - 900 = - 400$

$∴ x = 80$

$H e n c e t h e r e a r e 80 n o t e s o f R s 5 a n d 10 n o t e s o f R s 10.$

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