wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A sum of Rs 700 is used to give seven cash prizes to students of a school for their overall academic performance. If, each prize is Rs 20 less than its preceding term, find the value of each of the prizes.

Open in App
Solution

It is given that sum of seven cash prizes is equal to Rs 700.

And, each prize is Rs 20 less than its preceding term.

Let value of first prize = Rs a

Let value of second prize =Rs (a−20)

Let value of third prize = Rs (a−40)

So, we have sequence of the form:

a, a−20, a−40, a−60....

It is an arithmetic progression because the difference between consecutive terms is constant.

First term = a

Common difference = d = (a-20) - a = -20

n = 7 (Because there are total of seven prizes)

S7 = Rs 700 {given}

Applying formula, Sn=n2(2a+ (n−1) d) to find sum of n terms of AP , we get

S7=72(2a + (7−1) (−20))

700=72(2a−120)

200=2a−120

320=2a

a=3202

a=160

Therefore, value of first prize = Rs 160

Value of second prize = 160 - 20 = Rs 140

Value of third prize = 140 - 20 = Rs 120

Value of fourth prize = 120 - 20 = Rs 100

Value of fifth prize = 100 - 20 = Rs 80

Value of sixth prize = 80 - 20 = Rs 60

Value of seventh prize = 60 -20 = Rs 40


flag
Suggest Corrections
thumbs-up
34
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Formula for Sum of N Terms of an AP
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon