A sum of Rs 700 is used to give seven cash prizes to students of a school for their overall academic performance. If, each prize is Rs 20 less than its preceding term, find the value of each of the prizes.
It is given that sum of seven cash prizes is equal to Rs 700.
And, each prize is Rs 20 less than its preceding term.
Let value of first prize = Rs a
Let value of second prize =Rs (a−20)
Let value of third prize = Rs (a−40)
So, we have sequence of the form:
a, a−20, a−40, a−60....
It is an arithmetic progression because the difference between consecutive terms is constant.
First term = a
Common difference = d = (a-20) - a = -20
n = 7 (Because there are total of seven prizes)
S7 = Rs 700 {given}
Applying formula, Sn=n2(2a+ (n−1) d) to find sum of n terms of AP , we get
S7=72(2a + (7−1) (−20))
⇒700=72(2a−120)
⇒200=2a−120
⇒320=2a
⇒a=3202
⇒a=160
Therefore, value of first prize = Rs 160
Value of second prize = 160 - 20 = Rs 140
Value of third prize = 140 - 20 = Rs 120
Value of fourth prize = 120 - 20 = Rs 100
Value of fifth prize = 100 - 20 = Rs 80
Value of sixth prize = 80 - 20 = Rs 60
Value of seventh prize = 60 -20 = Rs 40