A summit curve is formed at the intersection of a 2% upgradient and 6% down gradient. To provide a stopping sight distance of 188 m, the length of summit curve needed will be

428.12 m

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294.53 m

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375.45 m

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642.62 m

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Solution

The correct option is D 642.62 m
$Let length of curve, L_{C} > S S D$
$∴ L_{C} = \frac{N S^{2}}{4.4} = \frac{(2 + 6) \times 188^{2}}{(4.4) \times 100} = 642.618 m ≃ 642.62 m$

$∵ L_{C} > S S D (i . e . 642.62 m > 188 m)$

Therefore, our assumption is correct and length of summit curve is 642.62 m.

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A summit curve is formed at the intersection of a 2% upgradient and 6% down gradient. To provide a stopping sight distance of 188 m, the length of summit curve needed will be

The correct option is D 642.62 mLet length of curve, LC>SSD ∴LC=NS24.4=(2+6)×1882(4.4)×100=642.618m≃642.62 m ∵LC>SSD(i.e.642.62m>188m) Therefore, our assumption is correct and length of summit curve is 642.62 m.