Question

(a) Sunita is half the age of her mother Geeta. Find their ages.
(i) After 4 years
(ii) Before 3 years

(b) A bus travels at 'v' km per hour. It is going from Daspur to Beespur. After the bus has travelled 5 hours, Beespur is still 20 km away. What is the distance from Daspur to Beespur? Express it using $v$.

(c) Sarita’s father’s age is 5 years more than 3 times Sarita’s age. What is her father's age?

[4 MARKS]

Answer 1

(a) Solution: 2 Marks (1 Mark for Geeta and 1 mark for Sunita)
(b) Solution: 1 Mark
(c) Solution: 1 Mark

(a) Let the present age of Sunita’s mother Geeta = $2x$ years

Present age of Sunita $=\frac{2x}{2}=xyears$

(i) After 4 years:
Age of Geeta $=(2x+4)years$
Age of Sunita $=(x+4)years$

(ii) Before 3 years
Age of Geeta $=(2x-3)years$
Age of Sunita $=(x-3)years$

(b) Speed of the bus = $v\frac{km}{hr}$ i.e. (in 1 hr bus travels $v$ km )

$\therefore$ Distance travelled by bus after 5 hrs = $5vkm$

Distance remaining to Beespur = $20km$

Distance from Daspur to Beespur
= Distance travelled by bus in 5 hrs + Distance remaining
= $(5v+20)km$

(c) Let Sarita's present age be x years
$\therefore$ three times of Sarita's age =3x years
$\therefore$ Sarita's father age = 3x + 5 years