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Question

A supersonic jet travelling at Mach 3.00 at an altitude of 20000 m is directly over a person at time t=0 as shown in Fig 2.89
Where will the plane be when it is finally heard?
(Assume the speed of sound in air is 335 m/s)
1745205_9e50f6f97edf43a9a35fb571d923c3ee.png

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Solution

Let speed of sound in air be 335m/s.

sinq=v/vs here vs is the speed of Mach 3.00

sinq=335/3(335)

q=19.5o

tanq=h/x

tan19.5°=20000/x

x=5.66×104meters

v=Dx/Dt

3(335)=5.66×104/Dt

t=56.3sec


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