A surface is hit elastically and normally by n balls per unit time, all the balls having the same mass m and moving with the same velocity u. The force on the surface is:
A
mnu2
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B
2mnu2
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C
0.5mnu2
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D
2mnu
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Solution
The correct option is D2mnu Velocity of ball initially vi=u^i
Since the collision is elastic, thus the ball will move with same speed but in opposite direction after collision.
Velocity of ball finally vf=−u^i
Change in momentum of each ball Δp=m(vf−vi)=−2mu^i
Magnitude of change in momentum of each ball |Δp|=2mukgm/s