A surface water treatment plant operates round the clock with a flow rate of 35 m3-min - The water temperature is 15-C and jar testing indicated an alum dosage of 25 mg-l - Gt - 4 - 104 for producing optimum result- The alum required for 30 days in kg is -

Q = 35 m^3/min Water temp = 15^∘ C Alum dose = 25 mg/l G_l= 4 × 10^4 Alum quantity req. for 30 days in kg = ? = 35 × 30 ×24 ×60×10^3 ×25 ×10^ 6 kg = 37 ...

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Standard XII

Chemistry

Oxides of Sulphur

A surface wat...

Question

A surface water treatment plant operates round the clock with a flow rate of $35 m^{3} / m i n$ . The water temperature is $15^{\circ} C$ and jar testing indicated an alum dosage of $25 m g / l$ ; $G_{t} = 4 \times 10^{4}$ for producing optimum result. The alum required for 30 days (in kg) is -
37800

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Solution

The correct option is A 37800
$Q = 35 m^{3} / m i n$

Water temp = $15^{\circ} C$

Alum dose = $25 m g / l$

$G_{l} = 4 \times 10^{4}$

Alum quantity req. for 30 days in kg = ?

$= 35 \times 30 \times 24 \times 60 \times 10^{3} \times 25 \times 10^{- 6} k g$

$= 37800 k g$

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A surface water treatment plant operates round the clock with a flow rate of 35 m3/min . The water temperature is 15∘C and jar testing indicated an alum dosage of 25 mg/l ; Gt=4×104 for producing optimum result. The alum required for 30 days (in kg) is -37800

The correct option is A 37800Q=35 m3/min Water temp = 15∘C Alum dose = 25 mg/l Gl=4×104 Alum quantity req. for 30 days in kg = ? =35×30×24×60×103×25×10−6 kg =37800 kg

The correct option is A 37800
$Q = 35 m^{3} / m i n$

Water temp = $15^{\circ} C$

Alum dose = $25 m g / l$

$G_{l} = 4 \times 10^{4}$

Alum quantity req. for 30 days in kg = ?

$= 35 \times 30 \times 24 \times 60 \times 10^{3} \times 25 \times 10^{- 6} k g$

$= 37800 k g$