A survey of $200$ people was conducted about their preference of visiting various pavilions.
Pavilion Good living Delhi Pavilion Toy Pavilion Defence Pavilion
No. of person $95$ $45$ $40$ $20$
Find the probability that a person selected at random visited for only Toy pavilion.

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Solution

We have to find the probability of good living and Delhi pavilion
Total numbers of people $= 200$
Total numbers of trial $= 200$
Let $E_{1}$ be the event of selected person visited only toy pavilion
Then, the number of trial in which $E_{1}$ , happened $= 40$
$\begin{array}{rcl} P (E_{1}) & = & \frac{N u m b e r o f t r i a l s i n w h i c s E_{1} h a p p e n e d}{T o t a l n u m b e r o f t r i a l s} \\ = & \frac{40}{200} \\ = & \frac{1}{5} \end{array}$
Hence, $\frac{1}{5}$ is the required probability.

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Pavilion	Good living	Delhi Pavilion	Toy Pavilion	Defence Pavilion
No. of person	$95$	$45$	$40$	$20$

A survey of 200 people was conducted about their preference of visiting various pavilions.PavilionGood livingDelhi PavilionToy PavilionDefence Pavilion No. of person95454020Find the probability that a person selected at random visited for only Toy pavilion.

A survey of $200$ people was conducted about their preference of visiting various pavilions.
Pavilion Good living Delhi Pavilion Toy Pavilion Defence Pavilion
No. of person $95$ $45$ $40$ $20$
Find the probability that a person selected at random visited for only Toy pavilion.