A survey of favorite snacks of 20 children are given below. Find the probability of the favorite snack to be the french fries.

30%

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33.33%

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25%

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20%

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Solution

The correct option is A 30%
We know,
$Probability = \frac{N u m b e r o f f a v o r a b l e o u t c o m e s}{T o t a l n u m b e r o f o u t c o m e s}$

Total number of children = 20

From the given table, we observe:

Type of snacks Numbers observed Probability

Cake 8 $\frac{8}{20} = 0.4 = 40 %$

Popcorn 6 $\frac{6}{20} = 0.3 = 30 %$

French fries 6 $\frac{6}{20} = 0.3 = 30 %$

Hence, the probability of the favorite snack to be French fries is 30%.

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Type of snacks	Numbers observed	Probability
Cake	8	$\frac{8}{20} = 0.4 = 40 %$
Popcorn	6	$\frac{6}{20} = 0.3 = 30 %$
French fries	6	$\frac{6}{20} = 0.3 = 30 %$