You visited us 1 times! Enjoying our articles? Unlock Full Access!

Single Point Continuity

A surveyor's ...

Question

A surveyor's $30 m$ steel tape is correct at a temperature of $20^{o} C$ . The distance between two points, as measured by this tape on a day when the temperature is $35^{o} C$ , is 26 m. What is the true distance between the points ?
$(α_{s t e e l} = 1.2 \times 10^{- 5} /^{o} C)$

26.00476

No worries! We‘ve got your back. Try BYJU‘S free classes today!

27.00468

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25.6658

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D none of these
$Δ l = l_{1} α Δ t$
$l_{1} = \frac{Δ l}{α Δ t}$
$l_{2} - l_{1} = l_{1} α Δ t$
$l_{2} = l_{1} (1 + α Δ t)$
$l_{1} = \frac{l_{2}}{1 + α Δ t} = \frac{26}{[1 + 1.2 \times 10^{- 5} \times (35 - 20)]} = \frac{26}{1 + 0.00018}$
$l_{1} = \frac{26}{1.00018} m = 25.99532$

Suggest Corrections

Similar questions

20^{\circ} C

35^{\circ} C

α_{s t e e l}

1.2 \times 10^{- 5} /^{\circ} C

20^{\circ} C

35^{\circ} C

α_{s t e e l}

1.2 \times 10^{- 5} /^{\circ} C

20^{\circ} C

- 15^{\circ} C

[α_{steel} = 1.2 \times 10^{- 5 \cdot 0} C^{- 1}]

20^{o}

- 15^{o}

α_{s t e e l}

10^{- 5^{o}} C^{- 1}

1 m

{27.0}^{o} C

63.0 c m

{45.0}^{o} C

{27.0}^{o} C

= 1.20 \times 10^{- 5} K^{- 1}

Join BYJU'S Learning Program