A sweet shopkeeper prepares 396 gulab jamuns and 342 rasgullas. He packs them into containers. Each container consists of either gulab jamun or rasgulla, but have equal number of pieces he should put in each container so that numbers of containers are least.

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Solution

$342 = 2 \times 3 \times 3 \times 19$ & $396 = 2 \times 2 \times 3 \times 3 \times 11$ .
We get $2 \times 3 \times 3$ as common in both factors. So $18$ is highest common factor.
$∴$ No. of pieces to be filled in a pack is $18$ for which no. of packs will be least.

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A sweet shopkeeper prepares 396 gulab jamuns and 342 rasgullas. He packs them into containers. Each container consists of either gulab jamun or rasgulla, but have equal number of pieces he should put in each container so that numbers of containers are least.

342=2×3×3×19 & 396=2×2×3×3×11.We get 2×3×3 as common in both factors. So 18 is highest common factor.∴ No. of pieces to be filled in a pack is 18 for which no. of packs will be least.

$342 = 2 \times 3 \times 3 \times 19$ & $396 = 2 \times 2 \times 3 \times 3 \times 11$ .
We get $2 \times 3 \times 3$ as common in both factors. So $18$ is highest common factor.
$∴$ No. of pieces to be filled in a pack is $18$ for which no. of packs will be least.