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Byju's Answer
Standard VII
Chemistry
Factors Affecting Evaporation
A swimmer com...
Question
A swimmer coming out from a pool is covered with a film of water weighing about 18g. How much heat must be supplied to evaporate this water at 298 K ?
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Solution
At 298 K in order to evaporate one mole of water, ∆Hvap will be used.
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Similar questions
Q.
A swimmer coming out from a pool is covered with a film of water weighing about
18
g. Calculate the amount of heat required to evaporate this water at
298
(
Δ
v
a
p
H
o
f
o
r
H
2
0
i
s
40.66
k
J
m
o
l
−
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)
Q.
A swimmer coming out from a pool is covered with a film of water weighing about
18
g. How much heat must be supplied to evaporate this water at
298
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100
o
C.
Δ
v
a
p
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⊝
for water at
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K
=
40.66
kJ
m
o
l
−
1
.
Q.
A swimmer coming out from a pool is covered with a film of water weighing about 18 g. Calculate the internal energy of vaporisation at
100
0
C
.
[ ∆
vap
H
for water at 373 K = 40.66 kJ mol
-1
]
Q.
10
g
m
of ice at
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o
C
is kept in a calorimeter of water equivalent
10
g
m
. How much heat should be supplied to the apparatus to evaporate the water thus formed? (Neglect loss of heat)
Q.
A closed thermally insulated vessel contains
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a
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560
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