wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A swimmer crosses a flowing stream of width ω to and fro in time t1. The time taken to cover the same distance up & down the stream is t2. if t3 is the time swimmer would take to swim a distance 2ω in still water, then:

A
t21=t2t3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
t22=t1t3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
t23=t1t3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
t3=t1+t2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A t21=t2t3
Let 'u' be the velocity of swimmer in still water and 'v' be velocity of river.

in case 1
Since v and u are perpendicular to each other.
t1=2(wu2v2)

In case 2nd
The swimmer goes upstream and downstream.
t2=wu+t+wut=2uwu2v2

In case 3rd
Still water
t3=2w4
We see t21=t2t3

Hence option (A) is correct

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Apparent Depth
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon