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Question

# A swimmer crosses a river with minimum possible time 10 second. And, when he reaches the other end starts swimming in the direction from where he started swimming. Keeping the direction fixed the swimmer crosses the river in 15 sec. the ratio of speed of swimmer with respect to water and the speed of river flow is (Assume constant speed of river & swimmer)

A
32
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B
94
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C
25
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D
52
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Solution

## The correct option is C 2√5Let v be the velocity of man w.r.t river, u be the velocity of flow in river and d be the width of river. Tme taken by man while going from A to B, dv=10.....(i) Tme taken by man while going from B to A, dvcosθ=15….(ii) tanθ=uv.…(iii) Solving the above 3 equations, we get v√u2+v2=23 vu=2√5

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