A swimmer's speed in the direction of flow of river is $16 k m h^{- 1} .$ Against the direction of flow of river, the swimmer's speed is $8 k m h^{- 1} .$ Calculate the swimmer's speed in still water and the velocity of flow of the river.

12 k m p h, 4 k m p h

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10 k m p h, 3 k m p h

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10 k m p h, 4 k m p h

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12 k m p h, 2 k m p h

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Solution

The correct option is A $12 k m p h, 4 k m p h$
Let the velocity of swimmer in still water be $V_{s r}$ and velocity of river flow be $V_{r}$
Then, as per question $V_{r} + V_{s r} = V_{s}$

$∴$ The swimmer's speed along the direction of flow of river water is
$V_{r} + V_{s r} = 16 . . . (1)$
The swimmer's speed against the flow of the river water is
$V_{s r} - V_{r} = 8 . . . (2)$
from equations $(1)$ and $(2)$
$V_{s r} = 12 k m / h$
$V_{r} = 4 k m / h$

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