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Question

# A swimmer swims in still water at a speed =5 km/hr. He enters a 200 m wide river, having river flow speed =4 km/hr at point A and proceeds to swim at an angle of 127∘ with the river flow direction. Another point B is located directly across A on the other side. The swimmer lands on the other bank at a point C, from which he walks the distance CB with a speed =3 km/hr. The total time in which he reaches from A to B is

A
5 minutes
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B
4 minutes
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C
3 minutes
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D
None
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Solution

## The correct option is B 4 minutesVS=VSR+VRVS=(VR−VSRSin30∘).(0.05)Displacement along x−axis=d=(VR−VSRSin37∘).(0.05) =[4−5(35)].(0.05) =0.05km =50mjourney time (only while swimming) = 200×10−3VVRcos37∘ = 0.05hrtotal time = 50×10−3km3km/hr+0.05hr= 0.053+0.05=0.203=0.0666hr=4mins

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