A swimmer wants to cross a 200m wide river which is flowing at a speed of 2m/s. The velocity of the swimmer with respect to river is 1m/s. How far from the point directly opposite to the straight point does the swimmer reach the opposite bank?

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Solution

Time taken by the swimmer to cross the river $= t = \frac{200}{1} = 200 s e c$
In that time horizontal shift of the swimmer =Drift $= D = 200 \times 2 = 400 m$

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A swimmer wants to cross a 200m wide river which is flowing at a speed of 2m/s. The velocity of the swimmer with respect to river is 1m/s. How far from the point directly opposite to the straight point does the swimmer reach the opposite bank?

Time taken by the swimmer to cross the river=t=2001=200secIn that time horizontal shift of the swimmer =Drift =D=200×2=400m

Time taken by the swimmer to cross the river $= t = \frac{200}{1} = 200 s e c$
In that time horizontal shift of the swimmer =Drift $= D = 200 \times 2 = 400 m$