CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A swimmer wishes to cross a 1km wide river flowing at 5kmh1. his speed in still waters is 3kmh1. He has to reach directly opposite in minimum possible time. If he does not reach directly opposite by swimming, he has to walk that distance at 5kmh1. Find the time taken.

A
0.36hr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.66hr
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1hr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.36hr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 0.66hr

letθbetheanglebetweentherelativeveloctiyofboatandalineperpendiculartotheflow.timetakentocrosstherivert1=13cosθtimetakentowhilewalkingt2=drift5=15(53sinθ3cosθ)totaltimet=13cosθ+15(53sinθ3cosθ)dtdθ=0sinθ=0.3t=0.66hrs


flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hyperbola and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon