A swimming pool is $24 m$ long and $! 5 m$ broad, when a number of men dive into the pool, the height of the water rises by $1 c m$ . If the average amount of water displaced by one of the men be $0.1 c u . m$ , how many men are there in the pool?

42

No worries! We‘ve got your back. Try BYJU‘S free classes today!

46

No worries! We‘ve got your back. Try BYJU‘S free classes today!

32

No worries! We‘ve got your back. Try BYJU‘S free classes today!

36

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $36$
Swimming pool $\to 24 m \times 15 m$
Let $n$ men dive in pool
One man displaces $0.1 c u . m$
So, $n$ men displaces $n (0.1) c u . m$
As $1 c m$ is displaced
So volume displaced $= 24 \times 15 \times 0.01$
n(0.1)= $24 \times 15 \times \frac{1}{100}$
n=36
Answer $D$

Suggest Corrections

Similar questions

Q. In a swimming pool measuring

90

m by

40

150

men take a dip. If the average displacement of water by a man is

8 m^{3}

, what will be the rise in water level ?

Q. A swimming pool appears to be raised by

6 m

when viewed normally. What is the refractive index of water if the actual depth of the swim-ming pool is

24 m

Q. 500 men took dip in a tank which is 80 m long, 50 m broad. What is the rise in water level if the average displacement of water by a man is 4 m³.

In a diving event of Olympics, one participant jumped from a plank 100m above the level of the swimming pool; before diving she tossed herself 5m up in the air, streamlined her body,performed 2 flips and dived right in the pool. What is the distance(d) and displacement (s) travelled by her till the point she hits the pool?

Q. 500 men took dip in a tank which is 80 m long, 50 m broad. What is the rise in water level if the average displacement of water by a man is 4

m^{3}

Join BYJU'S Learning Program

A swimming pool is 24m long and !5m broad, when a number of men dive into the pool, the height of the water rises by 1cm. If the average amount of water displaced by one of the men be 0.1cu.m, how many men are there in the pool?

The correct option is D 36Swimming pool →24m×15mLet n men dive in poolOne man displaces 0.1cu.mSo, n men displaces n(0.1)cu.mAs 1cm is displaced So volume displaced =24×15×0.01n(0.1)=24×15×1100n=36Answer D

A swimming pool is $24 m$ long and $! 5 m$ broad, when a number of men dive into the pool, the height of the water rises by $1 c m$ . If the average amount of water displaced by one of the men be $0.1 c u . m$ , how many men are there in the pool?

The correct option is D $36$
Swimming pool $\to 24 m \times 15 m$
Let $n$ men dive in pool
One man displaces $0.1 c u . m$
So, $n$ men displaces $n (0.1) c u . m$
As $1 c m$ is displaced
So volume displaced $= 24 \times 15 \times 0.01$
n(0.1)= $24 \times 15 \times \frac{1}{100}$
n=36
Answer $D$