A symmetrical die is thrown four times and getting a multiple of 2 is considered to be a success. Then the correct option(s) among the following is/are
A
mean of success =1
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B
mean of success =2
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C
variance of success =1
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D
variance of success =2
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Solution
The correct option is C variance of success =1 Given : n=4,p=36=12,q=12
So, mean =np=4×12=2
variance =npq=4×1212=1