Question

A syringe of diameter 1 cm having a nozzle of diameter 1 mm, is placed horizontally at a height 5 m from the ground an incompressible non-viscous liquid is filled in the syringe and the liquid is compressed by moving the piston at a speed of 0.5 $m{s}^{-1}$ the horizontal distance travelled by the liquid jet is (g= 10 $m{s}^{-2})$

• A. 90 m
• B. 80 m
• C. 60 m
• D. 50 m

Answer 1

The correct option is D 50 m

$A_1{V}_1=A_2{V}_2$

${r_1}^2{V}_1={r_2}^2{V}_2$

${\left(\frac{{10}^{-2}}{2}\right)}^2\times 0.5={\left(\frac{{10}^{-3}}{2}\right)}^2{V}_2$

$V_2=50m/s$

$R=V_2\sqrt{\frac{2h}{g}}$

$=50\sqrt{\frac{2\times 5}{10}}=50m$

Hence,

option $\left(D\right)$ is correct answer.