A system absorbs 500 J of heat and does work of 50J on it surroundings. The change in internal energy is:

450 J

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

550 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

400 J

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 450 J
Heat absorbed by the system, Q = 500 J
Work done by the system, w = – 50 J
According to the first law of thermodynamics
$Δ U = Q + w = 500 - 50 = 450 J$

Suggest Corrections

Similar questions

Q. A system absorbs

600

J of heat and work equivalent to

300

J on its surroundings.

The change in internal energy is:

Q. A system absorb

600 J

of heat and work equivalent to

300 J

on its surroundings. The change in internal is energy:

Q. The change in internal energy of a system that has absorbed

2 kcal

of heat and does

500 J

of work is

Q. Find the change in internal energy of the system when a system absorbs

2 k c a l

of heat and at the same time does

500 J

of work

A system performs $101.3 J$ of work on its surrounding and absorbs $15 K J$ of heat from surroundings. The change in internal energy of the system is:

Join BYJU'S Learning Program

A system absorbs 500 J of heat and does work of 50J on it surroundings. The change in internal energy is:

The correct option is A 450 JHeat absorbed by the system, Q = 500 J Work done by the system, w = – 50 J According to the first law of thermodynamics ΔU=Q+w=500−50=450J

The correct option is A 450 J
Heat absorbed by the system, Q = 500 J
Work done by the system, w = – 50 J
According to the first law of thermodynamics
$Δ U = Q + w = 500 - 50 = 450 J$