A system absorbs 640J heat and does work of 260J, the change in internal energy of the system will be:
A
+380J
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B
−380J
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C
+900J
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D
−900J
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Solution
The correct option is A+380J The system absorbs640J and the work system does on surroundings is 260J. Therefore by the first law of thermodynamics, the internal energy of the system increases by: △U=q−W=(640−260)=+380J.