1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Other
Other
System Model
A system cont...
Question
A system contains three programs and each requires three tape units for its operation. The minimum number of tape units which the system must have such that deadlocks never arise is_________.
Open in App
Solution
(3*2 tape units) + 1 tape unit =7
Suggest Corrections
1
Similar questions
Q.
An operating system contains 3 user processes each requiring 2 units of resource R. The minimum number of units of r such that no deadlocks will ever arise is
Q.
A computer system has 6 tape drives, with n process completing for them. Each process may need 3 tape drives. The maximum value of n for which the system is guaranteed to be deadlock free is
Q.
A system share 9 tape drives. The current allocation and maximum requirement of tape drives for three processes are shown below:
Process
Current Allocation
Maximum Requirement
P1
P2
P3
3
1
3
7
6
5
Which of the following best describes current state of the system?
Q.
Consider three processes having maximum requirement of resource type R is 5, 4 and 6. The minimum instance of R in the system so that system must be deadlock free is _____
Q.
A computer has six tape drives, with n processes competing for them. Each process may need two drives. What is the maximum value of n for the system to be deadlock free?
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
System Model
OTHER
Watch in App
Explore more
System Model
Other Other
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app