A system has a complex pole pair of (-1 ± j2) and a real zero of (-3). The steady state output to a unit step input is 2. The transfer function of the system is.
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Solution
Transfer function of the system is T.F.=K(s+3)(s+1+2j)(s+1−2j) =k(s+3)[(s+1)2−(2j)2] =K(s+3)(s2+1+2s+4)=K(s+3)(s2+2s+5)
at steady state lims→0s.(1s)k(s+3)(s2+2s+5)=2 ⇒K(0+3)(0+0+5)=2 ∴k=103 ∴T.F.=10(s+3)3(s2+2s+5)