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Question

A system has absorbed 5 kcal of heat and does 200 J of work. The change in internal energy of the system is

A
20.8 J
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B
20.8 kJ
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C
208 J
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D
2.08 kJ
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Solution

The correct option is B 20.8 kJ
Given,
Heat absorbed by system (+Q)=5×103×4.2=21×103 J
Work done by the system (+W)=200 J
From, 1st law of thermodynamics,
Q=ΔU+W
ΔU=20.8 kJ

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