A system has absorbed 5kcal of heat and does 200J of work. The change in internal energy of the system is
A
20.8J
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B
20.8kJ
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C
208J
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D
2.08kJ
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Solution
The correct option is B20.8kJ Given, Heat absorbed by system (+Q)=5×103×4.2=21×103J Work done by the system (+W)=200J From, 1st law of thermodynamics, Q=ΔU+W ⇒ΔU=20.8kJ