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Question

A system has two charges qA=2.5×107 and qB=2.5×107, located at point A: (0,0,15 cm), B: (0,0,15 cm)respectively. What are the total charge and electric dipole moment of the system?

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Solution

Charge on A, qA=2.5×107C
Charge on B, qB=2.5×107C
Therefore, total charge q will be
q=qA+qB
=2.5×107+2.5×107
=5×107C
Distance between two charges, a=15(15)=30cm=0.3m
Electron dipole moment,
p=q.a
=2.5×107×0.3
=7.5×107Cm (along z-axis)
Because the direction of dipole is always negative to positive.

1007522_1024570_ans_17354e7483f5417b98bc329342f2d2a8.png

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