A system has two charges qA=2.5×10−7 and qB=2.5×10−7, located at point A: (0,0,−15cm), B: (0,0,15cm)respectively. What are the total charge and electric dipole moment of the system?
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Solution
Charge on A, qA=2.5×10−7C
Charge on B, qB=2.5×10−7C
Therefore, total charge q will be
q=qA+qB
=2.5×10−7+2.5×10−7
=5×10−7C
Distance between two charges, a=15−(−15)=30cm=0.3m
Electron dipole moment,
p=q.a
=2.5×10−7×0.3
=7.5×10−7Cm (along z-axis)
Because the direction of dipole is always negative to positive.