A system is provided with 200cal of heat and the work done by the system on the surrounding is 40J. the internal energy
Correct option: (C)
From first law of thermodynamic,
△U=q+W
△U=Change in internal energy
q=Heat supplied
W=Work done
q=200 cal=200×4.2=840 J
W=−40J
△U=q+w=840−40=800 J
Hence, the correct option is (C).