A system is provided with 200cal of heat and the work done by the system on the surrounding is 40J. Calculate the change in internal energy of the system?
A
Increases by 600J
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B
Decreases by 800J
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C
Increases by 800J
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D
Increases by 160J
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Solution
The correct option is C Increases by 800J From the first law of thermodynamic, ΔU=q+W q=200cal=200×4.2=840J W=−40J(Because work is done by the system on the surrounding) ΔU=q+w=840−40=800J