A system of binary stars of masses mA and mB are moving in circular orbits of radii rA and rB respectively. If TA and TB are the time periods of masses mA and mA respectively, then
A
TATB=(rArB)3/2
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B
TA>TB(ifrA>rB)
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C
TA>TB(ifmA>mB)
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D
TA=TB
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Solution
The correct option is DTA=TB GmAmB(rA+rB)2=mArA4π2T2A=mBrB4π2T2B ⇒mArA=mBrB ∴TA=TB