A system of binary stars of masses mA and mB are moving in circular orbits of radii rA and rB respectively. If TA and TB are the time periods of masses mA and mB respectively, then
A
TATB=(rArB)3/2
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B
TA>TB(ifrA>rB)
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C
TA>TB(ifmA>mB)
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D
TA=TB[+3,−1]
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Solution
The correct option is DTA=TB[+3,−1]
Since both the stars move in circular orbit under influence of each other's forces, Applying F=ma to both the stars and using ω=2πT, we get