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Question

A system of two blocks of masses m=2 kg and M=8 kg is placed on a smooth table as shown in figure. The coefficient of static friction between two blocks is 0.5. The maximum horizontal force F that can be applied to the block of mass M so that the blocks move together will be

A
9.8N
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B
39.2N
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C
49N
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D
78.4N
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Solution

The correct option is C 49N

For 2 kg block:
amax=μg
amax=0.5×9.8=4.9 m/s2
(this is the common acceleration of both the blocks)
Also:
Fmax=(M+m)amax
Fmax=(8+2)×4.9=49 N

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