You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Dimensional Analysis

A system pend...

Question

A system pendulum is oscillating in a lift.If the lift is going down with constant velocity,the time period of the simple pendulum is $T_{1}$ .If the lift is going down with some retardation its time period is $T_{2}$ then

T_{1} > T_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

T_{1} < T_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T_{1} = T_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Depends upon the mass of the pendulum bob

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $T_{1} > T_{2}$

Time period of pendulum with constant velocity is given by
$T_{1} = 2 π \sqrt{\frac{l}{g}}$
while the time period of pendulum in a lift moving downwards with constant retardation is given by
$T_{2} = 2 π \sqrt{\frac{l}{g_{e f f}}} = 2 π \sqrt{\frac{l}{g - (- a)}} = 2 π \sqrt{\frac{l}{g + a}}$
its clear from above two equations that $T_{1} > T_{2}$ , Since denominator of the second equation is larger than that of first equation.

Suggest Corrections

Similar questions

A simple pendulum hanging from the ceiling of a stationary lift has a time period $T_{1}$ . When the lift moves downward with constant velocity, the time period is $T_{2}$ , then

Q. A simple pendulum hanging from the ceiling of a stationary lift has time period

t_{1}

. When the lift moves downward with constant velocity, the time period is

t_{2}

, then

Q. Consider the following data and choose the correct option.

1.

The time period of a simple pendulum, whose bob is a hollow metallic sphere is

T

2.

The time period of a simple pendulum is

T_{1},

when the bob is filled with sand,

3.

The time period of a simple pendulum is

T_{2},

when it is filled with mercury and

4.

The time period of a simple pendulum is

T_{3},

when it is half-filled with mercury as shown.

A bob of a simple pendulum of mass $40$ gm with a positive charge $4 \times 10^{- 6}$ is oscillating with a time period $T_{1}$ .An electric field of intensity $3.6 \times 10^{4} N / C$ is applied vertically upwards.Now the time period is $T_{2}$ the value of $\frac{T_{2}}{T_{1}}$ is $(g = 10 m / s^{2})$ :

A body is thrown vertically upwards with an initial velocity u. It passes a point at a height h above the ground at time $t_{1}$ while going up and at time $t_{2}$ while falling down. Then the relation between u, $t_{1}$ and $t_{2}$ is

Join BYJU'S Learning Program

A system pendulum is oscillating in a lift.If the lift is going down with constant velocity,the time period of the simple pendulum is T1.If the lift is going down with some retardation its time period is T2 then

A system pendulum is oscillating in a lift.If the lift is going down with constant velocity,the time period of the simple pendulum is $T_{1}$ .If the lift is going down with some retardation its time period is $T_{2}$ then