A system under goes a process in which $Δ E = + 300 J$ while absorbing 400 J of heater undergoing an expansion against 0.5 bar. What is the change in the volume (in L)?

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Solution

The correct option is C 2
Given: Change in internal energy, $△ E = 300$
Heat supplied $Q = 400$

Now, using the relation, $P_{e x t} = 0.5 b a r$

$△ E = Q + W$

$300 J = 400 J + (- P_{e x t} △ V)$ ; Note : $W = - P_{e x t} . △ V$

$- 100 J = - 0.5 b a r △ V$

$\Rightarrow (0.5 b a r) △ V = 100 J$

$(0.5 b a r) △ V = 1 L . b a r$ $1 L - b a r = 100 J o u l e$

$(0.5 b a r) △ V = 1 L . b a r$

$△ V = \frac{1 L . b a r}{0.5 b a r}$

$△ V = 2.0 L i t e r$

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A system under goes a process in which ΔE=+300J while absorbing 400 J of heater undergoing an expansion against 0.5 bar. What is the change in the volume (in L)?

A system under goes a process in which $Δ E = + 300 J$ while absorbing 400 J of heater undergoing an expansion against 0.5 bar. What is the change in the volume (in L)?