Question

A system undergoes a process in which $\Delta U=+300J$ while absorbing $400J$ of heat energy is undergoing an expression against $0.5bar$. What is the change in the volume (in L)?

• A. 4
• B. 5
• C. 2
• D. 3

Answer 1

The correct option is C 2

Given: Change in internal energy ($\Delta U$) = 300J

Heat absorbed (q) = 400 J

Pressure = 0.5 bar

Solution: Change in internal energy is given by,

$\Delta U$ = q + W

where, q is the heat absorbed ( or given ) by the system and W is work done or by the system.

As, work is done by the system, so W= -ve

$300=400-0.5\times \Delta V\times 100$

On simplifying we get,

$\Delta V$ = 2 L.

Hence, the correct option is (C).