A system undergoes a process in which $Δ U = + 300$ J while absorbing $400 j$ of heat energy and undergoing an expansion $0.5$ bar. What is the change in the volume(in L)?

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Solution

The correct option is C $2$
For first law of thermodynamics
$d q = d u + d w$

$400 J = 300 J + d w$

So, $d w = 100 J$

$d w = p d v$

$d v = \frac{d w}{p} (d w = 100 J, p = 0.5 b a r = 0.5 \times 11^{5} p a s c a l)$

$d v = \frac{100}{0.5} \times 100000$

$d v = \frac{2}{1000 m^{3}} (1 m^{3} = 1000 l i t)$

$d v = 2 l i t .$

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A system undergoes a process in which ΔU=+300J while absorbing 400j of heat energy and undergoing an expansion 0.5 bar. What is the change in the volume(in L)?

The correct option is C 2For first law of thermodynamicsdq=du+dw400J=300J+dwSo, dw=100Jdw=pdvdv=dwp(dw=100J,p=0.5bar=0.5×115pascal)dv=1000.5×100000dv=21000m3(1m3=1000lit)dv=2lit.

A system undergoes a process in which $Δ U = + 300$ J while absorbing $400 j$ of heat energy and undergoing an expansion $0.5$ bar. What is the change in the volume(in L)?