Question

A T.V tower has a height of 100m. How much population is covered by the T.V broadcast if the average population density around the town is $1000/{\text{km}}^2$ ?

• A. $40.2\times {10}^5$
• B. $19.5\times {10}^6$
• C. $29.5\times {10}^7$
• D. $9\times {10}^4$

Answer 1

The correct option is A

$40.2\times {10}^5$

Range d $=\sqrt{2Rh}$

Area $=\pi d^2=\pi \times 2Rh=40.2\times {10}^2{\text{km}}^2$

Population of area covered is $40.2\times {10}^2\times 1000=40.2\times {10}^5$