A table cover $4 m \times 2 m$ is spread on a table. Find the cost of polishing the top of $A$ the table at $R s 2.25$ per sq. m, if $25 c m$ table cover is hanging all round the table .

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Solution

Dimension of Table top
$l = 4 - 2 \times 0.25 = 3.5$
$b = 2 - 2 \times 0.25 = 1.5$
Area of rectangular table top $= l \times b$
$= 3.5 \times 1.5 = 5.25 m^{2}$
Cost of polishing $1 m^{2}$ table top $= R s . 2.25$
Total cost of polishing table top $= 5.25 \times 2.25$ $= R s . 11.8125$

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A table cover 4 m×2 m is spread on a table. Find the cost of polishing the top of A the table at Rs 2.25 per sq. m, if 25 cm table cover is hanging all round the table .

Dimension of Table topl=4−2×0.25=3.5b=2−2×0.25=1.5Area of rectangular table top =l×b=3.5×1.5=5.25 m2Cost of polishing 1 m2 table top =Rs. 2.25Total cost of polishing table top =5.25×2.25=Rs. 11.8125

A table cover $4 m \times 2 m$ is spread on a table. Find the cost of polishing the top of $A$ the table at $R s 2.25$ per sq. m, if $25 c m$ table cover is hanging all round the table .

Dimension of Table top
$l = 4 - 2 \times 0.25 = 3.5$
$b = 2 - 2 \times 0.25 = 1.5$
Area of rectangular table top $= l \times b$
$= 3.5 \times 1.5 = 5.25 m^{2}$
Cost of polishing $1 m^{2}$ table top $= R s . 2.25$
Total cost of polishing table top $= 5.25 \times 2.25$ $= R s . 11.8125$