A table cover $4 m \times 2 m$ is spread on a meeting table. If $25 c m$ of the table cover is hanging all around the table, find the cost of polishing the top of the table at Rs. $2.25$ per square meter.

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Solution

The correct option is B $12$
The table will have the dimensions, length $= 4 - 2 (0.25) = 3.5 m$
Breadth $= 2 - 2 (0.25) = 1.5 m$
Area of the table top $= l \times b = 3.5 \times 1.5 = 5.25 m^{2}$
Cost of polishing the top of the table at $R s 2.25$ per square meters
$= R s 2.25 \times 5.25 = R s . 11.8125 = R s . 12$

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A table cover 4m×2m is spread on a meeting table. If 25cm of the table cover is hanging all around the table, find the cost of polishing the top of the table at Rs. 2.25 per square meter.

The correct option is B 12The table will have the dimensions, length =4−2(0.25)=3.5mBreadth =2−2(0.25)=1.5mArea of the table top =l×b=3.5×1.5=5.25m2Cost of polishing the top of the table at Rs2.25 per square meters =Rs2.25×5.25=Rs.11.8125=Rs.12

A table cover $4 m \times 2 m$ is spread on a meeting table. If $25 c m$ of the table cover is hanging all around the table, find the cost of polishing the top of the table at Rs. $2.25$ per square meter.