Question

A table cover of dimensions 3 m 25 cm x 2 m 30 cm is spread on a table. If 30 cm of the table cover, is hanging all around the table, find the area of the table cover, which is hanging outside the top of the table. Also, find the cost of polishing the top at Rs.16 per square metre.

Answer 1

To find the cost of polishing the table top, we have to find its area for which we require its length and breadth.
Given, length of cover = 3m 25cm = 3.25 m and breadth of cover = 2m 30cm = 2.30 m
$\therefore$ Area of the table cover $=3.25\times 2.30=7.475m^2$
Since, 30 cm width of cloth is outside the table an each side.
$\therefore$ Length of the table $=3.25-2\times 0.30=2.65m[\because 1cm=\frac{1}{100}m]$
and breadth of the table = 2.30 - 2 x 0.30 = 1.70 m
$\therefore$ Area of the top of the table $=(2.65\times 1.70)m^2$
$=4.505m^2$
Area of the hanging table cover = Area of table cover - Area of the top of the table
$=(7.475-4.505)m^2$
$=2.97m^2$

It is given that, the cost of polishing the table top is at the rate of Rs.16 per square metre.Therefore, cost of polishing the top = Area $\times$ Rate per square metre$=4.505\times 16$
= Rs 72.08