A table top is $9 d m a n d 5 c m$ long and $6 d m a n d 5 c m$ broad. What will be the cost to polish it at the rate of $20$ paise per square centimetre?

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Solution

Firstly, we will convert the units in one form.
we know that, $1 d m = 10 c m$
$L e n g t h = 9 d m + 5 c m = 90 c m + 5 c m = 95 c m$
$B r e a d t h = 6 d m + 5 c m = 60 c m + 5 c m = 65 c m$
Now, finding the area of the table top.
$A r e a o f t a b l e t o p = L e n g t h \times B r e a d t h A r e a o f t a b e l t o p = 95 \times 65 = 6175 c m^{2}$
Cost of polishing $1 c m^{2} = 20 p a i s e$
Cost of polishing $6175 c m^{2} = 20 \times 6175 = 1, 23, 500 p a i s e$
Converting $1, 23, 500 p a i s e i n t o r u p p e e s = \frac{123500}{100} = ₹ 1235$
Hence, the cost of polishing the table top will be $₹ 1235$ .

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A table top is 9dmand5cm long and 6dmand5cm broad. What will be the cost to polish it at the rate of 20 paise per square centimetre?

A table top is $9 d m a n d 5 c m$ long and $6 d m a n d 5 c m$ broad. What will be the cost to polish it at the rate of $20$ paise per square centimetre?