A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in how many days?

4 days

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6 days

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8 days

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12 days

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16 days

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Solution

The correct option is B
6 days

A, B and C take $x, \frac{x}{2} a n d \frac{x}{3}$ days respectively to finish the work

Then, $(\frac{1}{x} + \frac{2}{x} + \frac{3}{x}) = \frac{1}{2}$
$\Rightarrow \frac{6}{x} = \frac{1}{2} \Rightarrow x = 12$

So, B takes 6 days to finish the work.

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A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in how many days?

The correct option is B 6 days A, B and C take x,x2 and x3 days respectively to finish the work Then,(1x+2x+3x)=12 ⇒6x=12⇒x=12 So, B takes 6 days to finish the work.

The correct option is B
6 days

A, B and C take $x, \frac{x}{2} a n d \frac{x}{3}$ days respectively to finish the work

Then, $(\frac{1}{x} + \frac{2}{x} + \frac{3}{x}) = \frac{1}{2}$
$\Rightarrow \frac{6}{x} = \frac{1}{2} \Rightarrow x = 12$

So, B takes 6 days to finish the work.