Question

A tall tank filled with water has an irregular shape as shown . The wall CD makes an angle of ${45}^o$ with the horizontal ; the wall AB is normal to the base BC. The lengths AB and CD are much smaller than the height h of water (figure not to scale)
Let $P_1,P_2$4 and $P_3$ be the pressures excreted by the water on the wall AB, base BC and the wall CD respectively. Density of water is p and g is acceleration due to gravity. Then, approximately

• A. $P_1=P_2=P_3$
• B. $P_1=0P_3=\frac{1}{\sqrt{2}}{P}_2$
• C. $P_1=P_3=\frac{1}{\sqrt{2}}{P}_2$
• D. $P_1=P_3=0,P_2=hpg$

Answer 1

The correct option is A $P_1=P_2=P_3$

Since the depth of all three are same so pressure will be same in every direction at same depth.

So $P_1=P_2=P_3$