The correct option is
B 1 : 2: 1 :: Tall homozygous : Tall heterozygous : Dwarf
When a tall true garden pea plant is crossed with a true dwarf plant. All the offspring obtained in the F1 generation were tall (Tt).
When the F1 plants were selfed the resulting genotypes were in the ratio of 1 : 2: 1 :: Tall homozygous : Tall heterozygous : Dwarf.
This can be explained by the following cross.
Parents TT x tt
| T | T |
t | Tt (Tall) | Tt (Tall) |
t | Tt (Tall) | Tt (Tall) |
F1 generation - All Tt (Tall plants)
On selfing plants of the F1 generation we get,
Tt x Tt
F2 generation : TT, Tt, Tt, tt (Tall and Dwarf plants in the ratio of 3:1)
Therefore,
Phenotypic ratio : 3 : 1
Tall : Dwarf
Genotypic Ratio : 1 : 2 : 1
TT (Homozygous) : Tt (Heterozygous) : tt (Homozygous)
Therefore, option b) 1 : 2: 1 :: Tall homozygous : Tall heterozygous : Dwarf is the correct option.